修复即将上映获取失败错误缓存

This commit is contained in:
mtvpls
2025-12-15 21:56:01 +08:00
parent ef5c2cde00
commit fb181d86f2

View File

@@ -137,41 +137,51 @@ export async function getTMDBUpcomingContent(
getTMDBUpcomingTVShows(apiKey),
]);
// 检查是否有错误
if (moviesResult.code !== 200 && tvShowsResult.code !== 200) {
// 两个请求都失败,返回错误
return { code: moviesResult.code, list: [] };
}
// 获取今天的日期(本地时区)
const today = new Date();
const todayStr = `${today.getFullYear()}-${String(today.getMonth() + 1).padStart(2, '0')}-${String(today.getDate()).padStart(2, '0')}`;
// 转换电影数据为统一格式,并过滤掉已上映的
const movies: TMDBItem[] = moviesResult.list
.filter((movie) => {
// 只保留未来上映的电影
return movie.release_date && movie.release_date >= todayStr;
})
.map((movie) => ({
id: movie.id,
title: movie.title,
poster_path: movie.poster_path,
release_date: movie.release_date,
overview: movie.overview,
vote_average: movie.vote_average,
media_type: 'movie' as const,
}));
const movies: TMDBItem[] = moviesResult.code === 200
? moviesResult.list
.filter((movie) => {
// 只保留未来上映的电影
return movie.release_date && movie.release_date >= todayStr;
})
.map((movie) => ({
id: movie.id,
title: movie.title,
poster_path: movie.poster_path,
release_date: movie.release_date,
overview: movie.overview,
vote_average: movie.vote_average,
media_type: 'movie' as const,
}))
: [];
// 转换电视剧数据为统一格式,并过滤掉已播出的
const tvShows: TMDBItem[] = tvShowsResult.list
.filter((tv) => {
// 只保留未来播出的电视剧
return tv.first_air_date && tv.first_air_date >= todayStr;
})
.map((tv) => ({
id: tv.id,
title: tv.name,
poster_path: tv.poster_path,
release_date: tv.first_air_date,
overview: tv.overview,
vote_average: tv.vote_average,
media_type: 'tv' as const,
}));
const tvShows: TMDBItem[] = tvShowsResult.code === 200
? tvShowsResult.list
.filter((tv) => {
// 只保留未来播出的电视剧
return tv.first_air_date && tv.first_air_date >= todayStr;
})
.map((tv) => ({
id: tv.id,
title: tv.name,
poster_path: tv.poster_path,
release_date: tv.first_air_date,
overview: tv.overview,
vote_average: tv.vote_average,
media_type: 'tv' as const,
}))
: [];
// 合并并返回
const allContent = [...movies, ...tvShows];